t=2t^2-3t+3,

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Solution for t=2t^2-3t+3, equation: 



t=2t^2-3t+3.

We move all terms to the left:

t-(2t^2-3t+3.)=0

We get rid of parentheses

-2t^2+t+3t-3.=0

We add all the numbers together, and all the variables

-2t^2+4t-3=0

a = -2; b = 4; c = -3;
Δ = b2-4ac
Δ = 42-4·(-2)·(-3)
Δ = -8
Delta is less than zero, so there is no solution for the equation

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